Thursday, February 6, 2020

Manhattan Distance Heuristic

#include<stdio.h>
#include<stdlib.h>
struct node{
 int arr[10][10];
 int i,j;
 int md;

};
int a[10][10];
struct node* head = NULL;
struct node* q[200];
int check(int n);
void insert(int n);

int r=0,c=0,gotit;
void operations(int k,int m,int n);
void display(int n);
main()
{
 int n=3;
 insert(n);
 display(n);

}

void insert(int n)
{
 int i,j,i1,j1;

 struct node *temp;
 temp = (struct node*)malloc(sizeof(struct node));
 printf("Enter 8 puzzle matrix");
 for(i=0;i<n;i++)
 {
  for(j=0;j<n;j++)
  {
   scanf("%d",&temp->arr[i][j]);
  }
 }
  printf("Enter 8 puzzle matrix goal state");
     for(i=0;i<n;i++)
      {
    for(j=0;j<n;j++)
       {

   scanf("%d",&a[i][j]);
       }
   }
  for(i=0;i<n;i++)
 {
  for(j=0;j<n;j++)
  {
   if(temp->arr[i][j]==0)
   {
 
    temp->i = i;
    temp->j = j;
   }
  }
 }
 int count=0;
for(i1=0;i1<n;i1++)
{
for(j1=0;j1<n;j1++)
{
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(temp->arr[i1][j1]==a[i][j])
{
if((i1+j1)-(i+j)>0)
{
count=count+(i1+j1)-(i+j);
}
else
{
count=count+(i+j)-(i1+j1);
}
}
}
}
}
}
temp->md=count;
 int k,m;
 q[r] = temp;
 while(1)
 {


   k = q[r]->i;
  m = q[r]->j;

  if(++k<n && m<n && (k>=0 && m>=0))
  {
   operations(k,m,n);
  }

  k = q[r]->i;
   m = q[r]->j;

  if(--k<n && m<n&& (k>=0 && m>=0))
  {
       operations(k,m,n);
   }

  k = q[r]->i;
   m = q[r]->j;

  if(k<n && --m<n&& (k>=0 && m>=0))
  {
  operations(k,m,n);
  }

  k = q[r]->i;
  m = q[r]->j;

  if(k<n && ++m<n&& (k>=0 && m>=0))
  {
  operations(k,m,n);
  }

  r++;
  struct node* swap;
  // This for loop is sorting acc to h(n)
  for(i=r;i<=c;i++)
  {
   for(j=r;j<=c-1;j++)
   {
    if(q[j]->md>q[j+1]->md)
    {
     swap = q[j];
     q[j] = q[j+1];
     q[j+1] = swap;
    }
   }
  }

   c=r;
  if(check(n)==-4)
 {
  break;
 }


 }
}
//
void operations(int k,int m,int n)
{

 int o,p,count=0;
  struct node* t;
  t = (struct node*)malloc(sizeof(struct node));
 int i,j;
  for(i=0;i<n;i++)
 {
  for(j=0;j<n;j++)
  {
   t->arr[i][j] = q[r]->arr[i][j];
 
  }
 }
 for(i=0;i<n;i++)
 {
  for(j=0;j<n;j++)
  {
   if(t->arr[i][j]==0)
   {
    o = i;
    p=j;
   }
  }
 }
 int swap = t->arr[o][p];
 t->arr[o][p] = t->arr[k][m];
 t->arr[k][m] = swap;
  for(i=0;i<n;i++)
 {
  for(j=0;j<n;j++)
  {
   if(t->arr[i][j]==0)
   {
     t->i = i;
     t->j = j;
   }
  }
 }
count =0;
int i1,j1;
for(i1=0;i1<n;i1++)
{
for(j1=0;j1<n;j1++)
{
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(t->arr[i1][j1]==a[i][j])
{
if((i1+j1)-(i+j)>0)
{
count=count+(i1+j1)-(i+j);
}
else
{
count=count+(i+j)-(i1+j1);
}
}
}
}
}
}
t->md=count;

 c++;
 q[c] = t;

}


int check(int n)

{

 int i,j,k,i1,i3,c1=0,c2,g2=0;

 int count=0;
  // here it is removing the node if duplicate matrix is present
  for(i=0;i<c;i++)

 {
  for(i3=i+1;i3<c;i3++)

  {
  count = 0 ;
for(j=0;j<n;j++)
    {
for(k=0;k<n;k++)

   {
       if(q[i]->arr[j][k]==q[i3]->arr[j][k])

    {

     count++;
     }
    }
 }
  if(count==9)

  {

       for(i1=i3;i1<c;i1++)

       {

        q[i1] = q[i1+1];

     

    }

    c--;

  count = 0;

 }



 count = 0;

 }



}

// here it is checking whether the goal state is finding or not

 c2=0;

for(i1=0;i1<c;i1++)

{
for(j=0;j<n;j++)

  {

   for(k=0;k<n;k++)

   {

 

    if(q[i1]->arr[j][k]==a[j][k])

    {

     c2++;

   

    }

   }

   }

  if(c2==9)

  {

   gotit = i1;

   g2 = -4;

   break;

  }

  else{

   c2=0;

  }

 }
return g2;
}
// Displaying path
void display(int n)
{
 int i,j,k;
 for(i=0;i<r;i++)
 {
  printf("\n");
  for(j=0;j<n;j++)
  {
   for(k=0;k<n;k++)
   {
    printf("%d\t",q[i]->arr[j][k]);
   }
   printf("\n");
  }

 }

}

Wednesday, February 5, 2020

misplaced tiles (heuristic) in c

#include<stdio.h>
#include<stdlib.h>
struct node{
int arr[10][10];
int i,j;
int h;

};
int a[10][10];
struct node* head = NULL;
struct node* q[200];
int check(int n);
void insert(int n);

int r=0,c=0,gotit;
void operations(int k,int m,int n);
void display(int n);
main()
{
int n=3;
insert(n);
display(n);

}

void insert(int n)
{
int i,j;

struct node *temp;
temp = (struct node*)malloc(sizeof(struct node));
printf("Enter 8 puzzle matrix");
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
scanf("%d",&temp->arr[i][j]);
}
}
printf("Enter 8 puzzle matrix goal state");
     for(i=0;i<n;i++)
      {
  for(j=0;j<n;j++)
       {

scanf("%d",&a[i][j]);
       }
   }
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(temp->arr[i][j]==0)
{

temp->i = i;
temp->j = j;
}
}
}
int count=0;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(temp->arr[i][j]!=a[i][j] && a[i][j]!=0)
{
  count++;
}
}
}
temp->h = count;
int k,m;
q[r] = temp;
while(1)
{


k = q[r]->i;
m = q[r]->j;

if(++k<n && m<n && (k>=0 && m>=0))
{
operations(k,m,n);
}

k = q[r]->i;
m = q[r]->j;

if(--k<n && m<n&& (k>=0 && m>=0))
{
      operations(k,m,n);
  }

k = q[r]->i;
m = q[r]->j;

if(k<n && --m<n&& (k>=0 && m>=0))
{
operations(k,m,n);
}

k = q[r]->i;
m = q[r]->j;

if(k<n && ++m<n&& (k>=0 && m>=0))
{
operations(k,m,n);
}

r++;
struct node* swap;
// This for loop is sorting acc to h(n)
for(i=r;i<=c;i++)
{
for(j=r;j<=c-1;j++)
{
if(q[j]->h>q[j+1]->h)
{
swap = q[j];
q[j] = q[j+1];
q[j+1] = swap;
}
}
}

c=r;
if(check(n)==-4)
{
break;
}


}
}
//
void operations(int k,int m,int n)
{

int o,p,count=0;
struct node* t;
t = (struct node*)malloc(sizeof(struct node));
int i,j;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
t->arr[i][j] = q[r]->arr[i][j];

}
}
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(t->arr[i][j]==0)
{
o = i;
p=j;
}
}
}
int swap = t->arr[o][p];
t->arr[o][p] = t->arr[k][m];
t->arr[k][m] = swap;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(t->arr[i][j]==0)
{
  t->i = i;
  t->j = j;
}
}
}
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(t->arr[i][j]!=a[i][j] && a[i][j]!=0)
{
count++;
}
}
}
t->h = count;
c++;
q[c] = t;

}


int check(int n)

{

int i,j,k,i1,i3,c1=0,c2,g2=0;

int count=0;
  // here it is removing the node if duplicate matrix is present
for(i=0;i<c;i++)

{
for(i3=i+1;i3<c;i3++)

{
count = 0 ;
for(j=0;j<n;j++)
{
for(k=0;k<n;k++)

{
if(q[i]->arr[j][k]==q[i3]->arr[j][k])

{

count++;
}
  }
}
if(count==9)

{

      for(i1=i3;i1<c;i1++)

      {

       q[i1] = q[i1+1];

       

  }

  c--;

count = 0;

}



count = 0;

}



}

// here it is checking whether the goal state is finding or not

c2=0;

for(i1=0;i1<c;i1++)

{
for(j=0;j<n;j++)

{

for(k=0;k<n;k++)

{



if(q[i1]->arr[j][k]==a[j][k])

{

c2++;



}

}

}

if(c2==9)

{

gotit = i1;

g2 = -4;

break;

}

else{

c2=0;

}

}
return g2;
}
// Displaying path
void display(int n)
{
int i,j,k;
for(i=0;i<r;i++)
{
printf("\n");
for(j=0;j<n;j++)
{
for(k=0;k<n;k++)
{
printf("%d\t",q[i]->arr[j][k]);
}
printf("\n");
}

}

}

Wednesday, January 29, 2020

shortest job first in c with gannt chart

#include<stdio.h>

void ganntchart(int p[],int arr2[],int n,int arr[]);

void displaytable(int arr[],int arr1[],int arr2[],int arr3[],int arr4[],int p[],int n);
main()
{

 int n,arr[15],arr1[15],arr2[15]={0},arr3[15],arr4[15],s=0,j1;
int p[15],k=0,sum=0;
float wt=0,tat=0;
int i,j,swap,swap1,swap2;
printf("Enter how many processers are there ");
scanf("%d",&n);
for(i=0;i<n;i++)
{
  p[i] = i+1;
printf("Enter p%d arival time",i+1);
scanf("%d",&arr[i]);

printf("Enter p%d burst time",i+1);
scanf("%d",&arr1[i]);

}

for(i=0;i<n;i++)
{
for(j=0;j<n-i-1;j++)
{
if(arr[j]>arr[j+1])
{
swap = arr[j];
arr[j] = arr[j+1];
arr[j+1] = swap;

swap1 = arr1[j];
arr1[j] = arr1[j+1];
arr1[j+1] = swap1;

swap2 = p[j];
p[j]= p[j+1];
p[j+1] = swap2;

}

}
}


for(i=0;i<n;i++)
{


 if( i==0)
 {
   s = arr1[i]+arr[i];
         arr2[i] = s;
   continue;
 }





  for(j1=i;j1<n;j1++)
  {
 
 
  for(j=i;j<n-1;j++)
  {
 
 
 
  if(arr1[j]>arr1[j+1] && arr[j+1]<=s)
  {
 

 swap = arr[j];
arr[j] = arr[j+1];
arr[j+1] = swap;

swap1 = arr1[j];
arr1[j] = arr1[j+1];
arr1[j+1] = swap1;

swap2 = p[j];
p[j]= p[j+1];
p[j+1] = swap2;
 
 
  }
 
 }

}
 s = s+arr1[i];
 arr2[i] = s;


}

//tat and wt
for(i=0;i<n;i++)
{
arr3[i] = arr2[i] - arr[i];
arr4[i] =  arr3[i] - arr1[i];
}
for(i=0;i<n;i++)
{
tat = tat+arr3[i];
wt = wt+arr4[i];
}
tat = tat/n;
wt = wt/n;
displaytable(arr,arr1,arr2,arr3,arr4,p,n);

ganntchart(p,arr2,n,arr);

printf("\n\nAverage turn around time is : %f \nAverage waiting time is :%f",tat,wt);

}

//    Display table


void displaytable(int arr[],int arr1[],int arr2[],int arr3[],int arr4[],int p[],int n)
{
 int i;
printf("\n                         printing table");
printf("\n                         --------------\n\n");

printf("p  |  Arival time  |  Burst time  |  complete time  |    TAT  |   WT  |\n");

 for(i=0;i<n;i++)
    {
     printf("p%2d      %2d             %2d               %2d              %2d       %2d  \n",p[i],arr[i],arr1[i],arr2[i],arr3[i],arr4[i]);
 }


}



// Gannt chart
void ganntchart(int p[],int arr2[],int n,int arr[])
{
int i,j,k=1;
printf("\n                         Gannt chart");
printf("\n                         ----------- \n");
printf("\n");

for(i=0;i<n;i++)
{
 printf(" ");
 for(j=0;j<k;j++)
 {


  printf("--");

 }

 k++;

}
printf("\n");

for(i=0;i<n;i++)
{
 printf("|p%d",p[i]);
 k= i*2;
 for(j=0;j<k;j++)
 {
  printf(" ");
 
 }
}



printf("|\n");
k=1;

for(i=0;i<n;i++)
{
 printf(" ");
 for(j=0;j<k;j++)
 {


  printf("--");

 }

 k++;

}
printf("\n");
printf("%d",arr[0]);
k=1;
int m=0;
for(i=0;i<n;i++)
{
  for(j=0;j<k;j++)
 {
  printf("  ");
 }

 k++;
 if(arr2[i]>=10)
 {
  if(m==0)
  {
   printf("%d",arr2[i]);
 
  }
  else
  {
   printf("\b");
   printf("%d",arr2[i]);
  }
  m++;
 }
 else
 {
  printf("%d",arr2[i]);
 }

}

}

Tuesday, January 28, 2020

8puzzle using bfs in c program

#include<stdio.h>
#include<stdlib.h>
struct node{
int arr[10][10];
struct node* link;
int i,j;

};
int a[10][10];
struct node* q[200];


int r=0,c=0,gotit=0;
void operations(int k,int m,int n);
void display(int n);
void insert(int n);
int check(int n);
main()
{
int n=3;
insert(n);
display(n);

}

void insert(int n)
{
int i,j;

struct node *temp;
temp = (struct node*)malloc(sizeof(struct node));
printf("Enter 8 puzzle matrix intial state");
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
scanf("%d",&temp->arr[i][j]);
}
}
printf("Enter 8 puzzle matrix goal state");
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
scanf("%d",&a[i][j]);
}
}
temp->link=NULL;
// here finding the zero position and zero index is storing in that particular node
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(temp->arr[i][j]==0)
{

temp->i = i;
temp->j = j;
}
}
}
int k,m;
q[r] = temp;
while(1)
{
if( check(n)==-4)
{
break;
}


k = q[r]->i;
m = q[r]->j;

 //down
if(++k<n && m<n && (k>=0 && m>=0))
{
operations(k,m,n);
}

k = q[r]->i;
m = q[r]->j;
//up
if(--k<n && m<n&& (k>=0 && m>=0))
{
      operations(k,m,n);
  }

k = q[r]->i;
m = q[r]->j;
//left
if(k<n && --m<n&& (k>=0 && m>=0))
{
operations(k,m,n);
}

k = q[r]->i;
m = q[r]->j;
// right
if(k<n && ++m<n&& (k>=0 && m>=0))
{
operations(k,m,n);
}

r++;
if( check(n)==-4)
{
break;
}


}
}
// operations
void operations(int k,int m,int n)
{

int o,p;
struct node* t;
t = (struct node*)malloc(sizeof(struct node));
int i,j;
// copying the parent node into child node
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
t->arr[i][j] = q[r]->arr[i][j];

}
}
// finding the zero positin
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(t->arr[i][j]==0)
{
o = i;
p=j;
}
}
}
// swaping the zero based up on left,right,up,down operations
int swap = t->arr[o][p];
t->arr[o][p] = t->arr[k][m];
t->arr[k][m] = swap;
//finding the zero position of child node
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(t->arr[i][j]==0)
{                                                                                                                                                 
  t->i = i;
  t->j = j;
}
}
}
t->link = q[r];
c++;
q[c] = t;

}
int check(int n)
{
int i,j,k,i1,i3,c1=0,c2,g2=0;
int count=0;

  // here it is removing the node if duplicate matrix is present

for(i=0;i<c;i++)
{


for(i3=i+1;i3<c;i3++)
{
count = 0 ;
for(j=0;j<n;j++)
{
for(k=0;k<n;k++)
{

if(q[i]->arr[j][k]==q[i3]->arr[j][k])
{
count++;

}
}

}
if(count==9)
{
      for(i1=i3;i1<c;i1++)
      {
       q[i1] = q[i1+1];
       
  }
  c--;
count = 0;
}

count = 0;
}

}
// here it is checking whether the goal state is finding or not
c2=0;
for(i1=0;i1<c;i1++)
{


for(j=0;j<n;j++)
{
for(k=0;k<n;k++)
{

if(q[i1]->arr[j][k]==a[j][k])
{
c2++;

}
}

}
if(c2==9)
{
gotit = i1;
g2 = -4;
break;
}
else{
c2=0;
}

}


return g2;

}
//Displaying
void display(int n)
{
printf("printing in reverse order\n");
struct node* t;

t=q[gotit];
int i,j;
while(t!=NULL)
{
for( i=0;i<n;i++)
{
for( j=0;j<n;j++)
{
printf("%d\t",t->arr[i][j]);
}
printf("\n");
}
printf("\n");
t = t->link;
}

}

Representation of 8puzzle

#include<stdio.h>
#include<stdlib.h>
struct node{
int arr[10][10];
int i,j;

};
struct node* head = NULL;
struct node* q[200];
void insert(int n);
void check(int n);
int r=0,c=0;
void operations(int k,int m,int n);
void display(int n);
main()
{
int n=3;
insert(n);
display(n);

}

void insert(int n)
{
int i,j;

struct node *temp;
temp = (struct node*)malloc(sizeof(struct node));
printf("Enter 8 puzzle matrix");
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
scanf("%d",&temp->arr[i][j]);
}
}
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(temp->arr[i][j]==0)
{

temp->i = i;
temp->j = j;
}
}
}
int k,m;
q[r] = temp;
while(1)
{
check(n);

if(r==100) break; // breaking at random point because it's just a representation of puzzle
k = q[r]->i;
m = q[r]->j;

if(++k<n && m<n && (k>=0 && m>=0))
{
operations(k,m,n);
}

k = q[r]->i;
m = q[r]->j;

if(--k<n && m<n&& (k>=0 && m>=0))
{
      operations(k,m,n);
  }

k = q[r]->i;
m = q[r]->j;

if(k<n && --m<n&& (k>=0 && m>=0))
{
operations(k,m,n);
}

k = q[r]->i;
m = q[r]->j;

if(k<n && ++m<n&& (k>=0 && m>=0))
{
operations(k,m,n);
}

r++;


}
}
//
void operations(int k,int m,int n)
{

int o,p;
struct node* t;
t = (struct node*)malloc(sizeof(struct node));
int i,j;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
t->arr[i][j] = q[r]->arr[i][j];

}
}
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(t->arr[i][j]==0)
{
o = i;
p=j;
}
}
}
int swap = t->arr[o][p];
t->arr[o][p] = t->arr[k][m];
t->arr[k][m] = swap;
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
if(t->arr[i][j]==0)
{
  t->i = i;
  t->j = j;
}
}
}

c++;
q[c] = t;

}
// checking whether the matrix are repeating are not
void check(int n)
{
int i,j,k,i1,i3;
int count=0;
for(i=0;i<c;i++)
{
for(i3=i+1;i3<c;i3++)
{

for(j=0;j<n;j++)
{
for(k=0;k<n;k++)
{

if(q[i]->arr[j][k]==q[i3]->arr[j][k])
{
count++;
}
}

}
if(count==9)
{
      for(i1=i3;i1<c;i1++)
      {
       q[i1] = q[i1+1];
       
  }
  c--;
count = 0;
}

count = 0;
}


}
}
void display(int n)
{
int i,j,k;
for(i=0;i<r;i++)
{
printf("\n");
for(j=0;j<n;j++)
{
for(k=0;k<n;k++)
{
printf("%d\t",q[i]->arr[j][k]);
}
printf("\n");
}

}

}

Thursday, January 23, 2020

depth first search in c program

#include<stdio.h>
#include<stdlib.h>
struct node{
int data;
struct node* left;
struct node* right;
};
struct node* root = NULL;


void insert();
void dfs();
int main()
{

int size=0;
int choice;
while(1)
{

printf("\nEnter 1-> to insert the data\n");
printf("Enter 2->to display\n");
printf("Enter 3 - > to exit");
printf("Enter your choice\n");
scanf("%d",&choice);
switch(choice)
{
case 1 :  insert();
break;
case 2 : dfs();
break;
case 3 : exit(0);
break;
}

}
}

void insert()
{


struct node* temp;
temp = (struct node*)malloc(sizeof(struct node));
printf("Enter data");
scanf("%d",&temp->data);
temp->left = NULL;
temp->right = NULL;
if(root==NULL)
{
root = temp;
}
else
{
struct node* p = root;
struct node* q = NULL;
while(p!=NULL)
{
q = p;
if(temp->data>p->data)
{
p=p->right;
}
else
{
p = p->left;
}
}
if(temp->data>q->data)
{
q->right = temp;


}
else
{
q->left = temp;
}
}

}

void dfs()
{
struct node* store;
struct node* q[100];
    int c= 0;
int s[100];
int i,r=-1;
q[c] = root;
if(q[c]==NULL)
{
printf("Nothing to display");
}
else
   {
   
     while(1)
     {
   
      if(q[c]->left!=NULL && q[c]->right!=NULL)
      {
     
      s[++r] = q[c]->data;
      store = q[c];
     
      q[c] =store->right;
     
      q[++c]=store->left;
}
else if(q[c]->left!=NULL && q[c]->right==NULL)
      {
      s[++r] = q[c]->data;
      q[c] = q[c]->left;
     
     
}
else if(q[c]->left==NULL && q[c]->right!=NULL)
      {
      s[++r] = q[c]->data;
      q[c] = q[c]->right;
     
}
else if(q[c]->left==NULL && q[c]->right==NULL)
      {
      s[++r] = q[c]->data;
     
      c--;
      if(c==-1) break;
}


}

 
   }
   for(i=0;i<=r;i++)
   {
    printf("%d\t",s[i]);
   }
   


}

FCFS Scheduling with gannt chart and table in c program


#include<stdio.h>
void ganntchart(int p[],int arr2[],int n);

void displaytable(int arr[],int arr1[],int arr2[],int arr3[],int arr4[],int p[],int n);
int main()
{
/*
where arr for arival time
arr1 for burst time
arr2 for c.t
arr3 for tat
arr4 for waiting time
*/
int n,arr[15],arr1[15],arr2[15]={0},arr3[15],arr4[15],s=0;
int p[15];
float wt=0,tat=0;
int i,j,swap,swap1;
printf("Enter how many processers are there ");
scanf("%d",&n);
for(i=0;i<n;i++)
{
p[i] = i+1;
printf("Enter p%d arival time",i+1);
scanf("%d",&arr[i]);

printf("Enter p%d burst time",i+1);
scanf("%d",&arr1[i]);

}


for(i=0;i<n;i++)
{
for(j=0;j<n-i-1;j++)
{
if(arr[j]>arr[j+1])
{
swap = arr[j];
arr[j] = arr[j+1];
arr[j+1] = swap;

swap1 = arr1[j];
arr1[j] = arr1[j+1];
arr1[j+1] = swap1;

int swap2 = p[j];
p[j]= p[j+1];
p[j+1] = swap2;

}

}
}
//ct
for(i=0;i<n;i++)
{
s = s+arr1[i];
arr2[i] = s;
}
//tat and wt
for(i=0;i<n;i++)
{
arr3[i] = arr2[i] - arr[i];
arr4[i] =  arr3[i] - arr1[i];
}
for(i=0;i<n;i++)
{
tat = tat+arr3[i];
wt = wt+arr4[i];
}
tat = tat/n;
wt = wt/n;
displaytable(arr,arr1,arr2,arr3,arr4,p,n);

ganntchart(p,arr2,n);

printf("\n\nAverage turn around time is : %f \nAverage waiting time is :%f",tat,wt);

}

//    Display table


void displaytable(int arr[],int arr1[],int arr2[],int arr3[],int arr4[],int p[],int n)
{
int i;
printf("\n                         printing table");
printf("\n                         --------------\n\n");

printf("p  |  Arival time  |  Burst time  |  complete time  |    TAT  |   WT  |\n");
 
for(i=0;i<n;i++)
    {
     printf("p%2d      %2d             %2d               %2d              %2d       %2d  \n",p[i],arr[i],arr1[i],arr2[i],arr3[i],arr4[i]);
}


}



// Gannt chart
void ganntchart(int p[],int arr2[],int n)
{
int i,j,k=1;
printf("\n                         Gannt chart");
printf("\n                         ----------- \n");
printf("\n");

for(i=0;i<n;i++)
{
printf(" ");
for(j=0;j<k;j++)
{


printf("--");

}

k++;

}
printf("\n");

for(i=0;i<n;i++)
{
printf("|p%d",p[i]);
k= i*2;
for(j=0;j<k;j++)
{
printf(" ");

}
}



printf("|\n");
k=1;

for(i=0;i<n;i++)
{
printf(" ");
for(j=0;j<k;j++)
{


printf("--");

}

k++;

}
printf("\n");
printf("0");
k=1;
int m=0;
for(i=0;i<n;i++)
{
for(j=0;j<k;j++)
{
printf("  ");
}

k++;
if(arr2[i]>=10)
{
if(m==0)
{
printf("%d",arr2[i]);

}
else
{
printf("\b");
printf("%d",arr2[i]);
}
m++;
}
else
{
printf("%d",arr2[i]);
}

}

}


Manhattan Distance Heuristic

#include<stdio.h> #include<stdlib.h> struct node{  int arr[10][10];  int i,j;  int md; }; int a[10][10]; struct node*...